Write equations for the horizontal and vertical components of the tension in the string and the weight (mg) of the m. The horizontal forces are: ma=TsinA (1) and the vert. forces are: mg=TcosA (2). Dividing (1) by (2) gives: a/g=tanA, and solving for a we have, a=gtanA. Therefore a=9.8 m/s^2tan7.9=1.4 m/s^2.
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